OUTER JOIN
FULL OUTER JOIN 关键字只要左表(table1)和右表(table2)其中一个表中存在匹配,则返回行.
FULL OUTER JOIN 关键字结合了 LEFT JOIN 和 RIGHT JOIN 的结果。
注:MySQL 数据库不支持全连接,想要实现全连接可以使用 UNION ALL 来将左连接和右连接结果组合在一起
1 OUTER JOIN 基本语法
SELECT column_name(s)
FROM table1
FULL OUTER JOIN table2
ON table1.column_name=table2.column_name;

演示数据库
在本教程中,我们将使用 LintCode 样本数据库。
下面是选自 "teachers" 教师表的数据:

下面是 "courses" 课程表的数据:

2 OUTTER JOIN 实例
下面的 SQL 语句查询所有的课程姓名和对应的教师姓名。
MySQL中不支持 FULL OUTER JOIN,你可以在 SQL Server 测试以下实例。
SELECT c.name AS course_name, t.name AS teacher_name
FROM courses c
FULL OUTER JOIN teachers t ON c.teacher_id = t.id;
注释:FULL OUTER JOIN 关键字返回左表(courses)和右表(teachers)中所有的行。如果 "teachers" 表中的行在 "courses" 中没有匹配或者 "courses" 表中的行在 "teachers" 表中没有匹配,也会列出这些行。
OUTER JOIN 在 MySQL 中的写法,可以通过 UNION 合并LEFT JOIN 和
SELECT c.name AS course_name, t.name AS teacher_name
FROM courses c
LEFT JOIN teachers t ON c.teacher_id = t.id
UNION
SELECT c.name AS course_name, t.name AS teacher_name
FROM courses c
RIGHT JOIN teachers t ON c.teacher_id = t.id;
执行输出结果
mysql> SELECT c.name AS course_name, t.name AS teacher_name
-> FROM courses c
-> LEFT JOIN teachers t ON c.teacher_id = t.id
-> UNION
-> SELECT c.name AS course_name, t.name AS teacher_name
-> FROM courses c
-> RIGHT JOIN teachers t ON c.teacher_id = t.id;
+-------------------------+------------------+
| course_name | teacher_name |
+-------------------------+------------------+
| Senior Algorithm | Southern Emperor |
| System Design | Western Venom |
| Django | Western Venom |
| Web | Southern Emperor |
| Big Data | Eastern Heretic |
| Artificial Intelligence | Western Venom |
| Java P6+ | Western Venom |
| Data Analysis | Eastern Heretic |
| Object Oriented Design | Southern Emperor |
| Dynamic Programming | Eastern Heretic |
| NULL | Northern Beggar |
| NULL | Linghu Chong |
+-------------------------+------------------+
12 rows in set (0.01 sec)
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